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let-x-and-y-such-that-2x-2-4x-2y-0-y-2-x-6-2-0-find-the-possibles-value-of-x-y-




Question Number 34211 by candre last updated on 02/May/18
let x and y such that  2x^2 +4x−2y=0  y^2 −(x+6)^2 =0  find the possibles value of x+y
letxandysuchthat2x2+4x2y=0y2(x+6)2=0findthepossiblesvalueofx+y
Answered by MJS last updated on 02/May/18
I. 2x^2 +4x−2y=0  II. y^2 −(x+6)^2 =0 ⇒ y=±(x+6)  case 1  y=−x−6 ⇒ x+y=−6  2x^2 +4x−2(−x−6)=0  2x^2 +6x+12=0  x_1 =−(3/2)−((√7)/2)i; y_1 =−(9/2)+((√7)/2)i  x_2 =−(3/2)+((√7)/2)i; y_2 =−(9/2)−((√7)/2)i  case 2  y=x+6  2x^2 +4x−2(x+6)=0  2x^2 +2x−12=0  x_3 =−3; y_3 =3  x_4 =2; y_4 =8    x, y∈C ⇒ (x+y)∈{−6; 0; 10}  x, y∈R ⇒ (x+y)∈{0; 10}
I.2x2+4x2y=0II.y2(x+6)2=0y=±(x+6)case1y=x6x+y=62x2+4x2(x6)=02x2+6x+12=0x1=3272i;y1=92+72ix2=32+72i;y2=9272icase2y=x+62x2+4x2(x+6)=02x2+2x12=0x3=3;y3=3x4=2;y4=8x,yC(x+y){6;0;10}x,yR(x+y){0;10}

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