Question Number 96685 by Ar Brandon last updated on 03/Jun/20
$$\underset{\omega\rightarrow\infty} {\mathrm{lim}20log}\sqrt{\mathrm{1}+\left(\frac{\omega}{\mathrm{100}}\right)^{\mathrm{2}} } \\ $$
Answered by Rio Michael last updated on 04/Jun/20
$$\mathrm{By}\:\mathrm{l}'\mathrm{hopitals}\:\mathrm{rule}\:\mathrm{i}\:\mathrm{get}\:+\infty\:\mathrm{as}\:\mathrm{answer} \\ $$