Question Number 82426 by zainal tanjung last updated on 21/Feb/20
$$\mathrm{Lim}\:\frac{\mathrm{e}^{\mathrm{x}} −\mathrm{1}−\mathrm{x}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} }\:=\:… \\ $$$$\mathrm{x}\rightarrow\mathrm{0} \\ $$
Commented by jagoll last updated on 21/Feb/20
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{e}^{{x}} −\mathrm{1}}{\mathrm{4}{x}^{\mathrm{3}} +\mathrm{3}{x}^{\mathrm{2}} +\mathrm{2}{x}}\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{e}^{{x}} }{\mathrm{12}{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$
Commented by zainal tanjung last updated on 21/Feb/20
$$\mathrm{Thanks}\:\mathrm{Sir} \\ $$