lim-n-2-n-sin-pi-2-n-

Question Number 103749 by bobhans last updated on 17/Jul/20

\lim_{n \to \infty} 2^{n} \sin (\frac{π}{2^{n}}) = ?

Answered by bramlex last updated on 17/Jul/20

s e t x = \frac{π}{2^{n}} \Rightarrow 2^{n} = \frac{π}{x}; x \to 0

\lim_{x \to 0} \frac{π}{x} . \sin x = π \lim_{x \to 0} \frac{\sin x}{x} = π .

Answered by Sobir last updated on 17/Jul/20

t h e a n s v e r i s π

Answered by Dwaipayan Shikari last updated on 17/Jul/20

\lim_{n \to \infty} π \frac{s i n \frac{π}{2^{n}}}{\frac{π}{2^{n}}} = π