lim-n-k-1-n-1-k-1-k-

Question Number 106240 by pticantor last updated on 03/Aug/20

l i \underset{n \to + \infty}{m} \underset{k = 1}{\sum^{n}} \frac{{(- 1)}^{k + 1}}{k} = ? ? ? ?

Answered by Dwaipayan Shikari last updated on 03/Aug/20

1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6} + \dots . = l o g (1 + 1) = l o g (2)

Commented by Ari last updated on 05/Aug/20

but how so? could you explain please!