Question Number 42367 by Joel578 last updated on 24/Aug/18
$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\left(\sqrt[{{n}^{\mathrm{2}} +{n}}]{\:\begin{pmatrix}{{n}}\\{\mathrm{0}}\end{pmatrix}\begin{pmatrix}{{n}}\\{\mathrm{1}}\end{pmatrix}\begin{pmatrix}{{n}}\\{\mathrm{2}}\end{pmatrix}…\begin{pmatrix}{{n}}\\{{n}}\end{pmatrix}}\right) \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 24/Aug/18
$${T}_{{n}} ={nc}_{\mathrm{0}} ×{nc}_{\mathrm{1}} ×{nc}_{\mathrm{2}} …×{nc}_{{n}} \\ $$$${T}_{{n}} =\frac{{n}!}{\mathrm{0}!\left({n}−\mathrm{0}\right)!}×\frac{{n}!}{\mathrm{1}!\left({n}−\mathrm{1}\right)!}×\frac{{n}!}{\mathrm{2}!\left({n}−\mathrm{2}\right)!}×…×\frac{{n}!}{{n}!\left({n}−{n}\right)!} \\ $$$${T}_{{n}} =\frac{\left({n}!\right)^{{n}} }{\left(\mathrm{0}!×\mathrm{1}!×\mathrm{2}!×\mathrm{3}!..×{n}!\right)\left\{\left({n}−\mathrm{0}\right)!×\left({n}−\mathrm{1}\right)!×\left({n}−\mathrm{2}\right)!×..×\left({n}−{n}\right)!\right\}} \\ $$$${T}_{{n}} =\frac{\left({n}!\right)^{\mathrm{2}} }{\left(\mathrm{1}!×\mathrm{2}!×\mathrm{3}!…×{n}!\right)^{\mathrm{2}} } \\ $$$${T}_{{n}} =\frac{\mathrm{1}}{\left(\frac{\mathrm{1}!}{{n}!}×\frac{\mathrm{2}!}{{n}!}×\frac{\mathrm{3}!}{{n}!}×…×\frac{{n}!}{{n}!}\right)^{\mathrm{2}} } \\ $$$${li}\underset{{n}\rightarrow\infty} {{m}}\:\left[\frac{\mathrm{1}}{\left(\frac{\mathrm{1}!}{{n}!}×\frac{\mathrm{2}!}{{n}!}×\frac{\mathrm{3}!}{{n}!}×…×\frac{{n}!}{{n}!}\right)^{\mathrm{2}} }\right]^{\frac{\mathrm{1}}{{n}^{\mathrm{2}} +{n}}} \\ $$$${contd}… \\ $$