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lim-n-sin-n-4-n-3-n-2-n-1-n-2-4-




Question Number 98004 by Ar Brandon last updated on 11/Jun/20
lim_(n→∞) [sin(n)+4^n ×(3/n^2 )×((n+1)/(n^2 −4))]
limn[sin(n)+4n×3n2×n+1n24]
Commented by bobhans last updated on 11/Jun/20
lim_(n→∞)  ((sin n)/n) × lim_(n→∞)  ((3.4^n )/n) ×lim_(n→∞)  ((n+1)/(n^2 −4))  = 0 × ∞ × 0 = 0   [ lim_(n→∞)  ((3.4^n )/n) = 3 × lim_(n→∞)  ((ln(4).4^n )/1) = ∞ ]
limnsinnn×limn3.4nn×limnn+1n24=0××0=0[limn3.4nn=3×limnln(4).4n1=]

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