Question Number 117898 by bobhans last updated on 14/Oct/20
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\:\mathrm{1}}{\mathrm{sin}\:^{\mathrm{4}} \mathrm{x}}\:\left(\mathrm{sin}\:\left(\frac{\mathrm{x}}{\mathrm{x}+\mathrm{1}}\right)−\frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{1}+\mathrm{sin}\:\mathrm{x}}\:\right)\:=? \\ $$
Answered by Lordose last updated on 14/Oct/20
$$\frac{\mathrm{1}}{\mathrm{6}}\:\left(\mathrm{rough}\:\mathrm{work}\right) \\ $$