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lim-x-0-e-x-e-x-2-x-2-




Question Number 87153 by jagoll last updated on 03/Apr/20
lim_(x→0)  ((e^x +e^(−x) −2)/x^2 )
limx0ex+ex2x2
Commented by john santu last updated on 03/Apr/20
lim_(x→0)  ((e^x −e^(−x) )/(2x)) = lim_(x→0)  ((e^x +e^(−x) )/2) = 1
limx0exex2x=limx0ex+ex2=1
Commented by mathmax by abdo last updated on 03/Apr/20
we have e^x  =1+(x/(1!)) +(x^2 /(2!)) +o(x^3 )  (x→0)  e^(−x) =1−(x/(1!)) +(x^2 /(2!)) +o(x^3 ) ⇒e^x  +e^(−x) −2 = x^2  +o(x^3 ) ⇒  ((e^x  +e^(−x) −1)/x^2 ) =1+o(x) ⇒lim_(x→0)    ((e^x  +e^(−x) −2)/x^2 )=1
wehaveex=1+x1!+x22!+o(x3)(x0)ex=1x1!+x22!+o(x3)ex+ex2=x2+o(x3)ex+ex1x2=1+o(x)limx0ex+ex2x2=1
Answered by $@ty@m123 last updated on 03/Apr/20
lim_(x→0)  ((e^x +(1/e^x )−2)/x^2 )  lim_(x→0)  ((e^(2x) +1−2e^x )/(x^2 .e^x ))  lim_(x→0)  (((e^x −1)^2 )/(x^2 .e^x ))  lim_(x→0)  (((e^x −1)/x))^2 ×(1/(lim_(x→0)   e^x ))  =1^2 ×1  =1
limx0ex+1ex2x2limx0e2x+12exx2.exlimx0(ex1)2x2.exlimx0(ex1x)2×1limx0ex=12×1=1

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