Question Number 118228 by bobhans last updated on 16/Oct/20
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sum_{\mathrm{r}=\mathrm{1}} ^{\mathrm{10}} \left(\mathrm{x}+\mathrm{r}\right)^{\mathrm{2020}} }{\left(\mathrm{x}^{\mathrm{1008}} +\mathrm{1}\right)\left(\mathrm{3x}^{\mathrm{1012}} +\mathrm{1}\right)}\:=?\: \\ $$
Answered by MJS_new last updated on 16/Oct/20
$$\mathrm{simply}\:\mathrm{put}\:{x}=\mathrm{0} \\ $$$$\mathrm{answer}\:\mathrm{is}\:\underset{{r}=\mathrm{1}} {\overset{\mathrm{10}} {\sum}}{r}^{\mathrm{2020}} \:\mathrm{which}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{calculated} \\ $$
Commented by bobhans last updated on 16/Oct/20
$${yes} \\ $$