Menu Close

lim-x-0-sec-6x-cos-2x-2x-tan-5x-




Question Number 83943 by jagoll last updated on 08/Mar/20
lim_(x→0)  ((sec 6x−cos 2x)/(2x tan 5x))
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sec}\:\mathrm{6x}−\mathrm{cos}\:\mathrm{2x}}{\mathrm{2x}\:\mathrm{tan}\:\mathrm{5x}} \\ $$$$ \\ $$
Answered by jagoll last updated on 08/Mar/20

Leave a Reply

Your email address will not be published. Required fields are marked *