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lim-x-0-sec-sin-1-1-x-3-x-




Question Number 115167 by bemath last updated on 28/Sep/20
   lim_(x→0)  ((sec  (sin^(−1) (1−x)))/(3(√x))) = ?
limx0sec(sin1(1x))3x=?
Answered by bobhans last updated on 28/Sep/20
 lim_(x→0)  ((sec  (sin^(−1) (1−x)))/(3(√x))) =?  remaining sec  (sin^(−1) (1−x)) = (√(2x−x^2 ))  so the limit can write as   lim_(x→0)  ((√(2x−x^2 ))/(3(√x))) = lim_(x→0)  (((√x) .(√(2−x)))/(3(√x))) = ((√2)/3)
limx0sec(sin1(1x))3x=?remainingsec(sin1(1x))=2xx2sothelimitcanwriteaslimx02xx23x=limx0x.2x3x=23

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