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lim-x-0-x-1-x-1-x-

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Question Number 104606 by john santu last updated on 22/Jul/20
lim_(x→0) {((x−1)/(∣x−1∣)) + ∣x∣}=?
limx→0{x−1∣x−1∣+∣x∣}=?
Answered by bobhans last updated on 22/Jul/20
(1)lim_(x→0^+ ) {((x−1)/(∣x−1∣)) + ∣x∣ } = lim_(x→0^+ ) {((x−1)/(x−1))+x}=1 (2) lim_(x→0^− ) {((x−1)/(∣x−1∣))−x}=lim_(x→0^+ ) {((x−1)/(x−1))−x}=1
(1)limx→0+{x−1∣x−1∣+∣x∣}=limx→0+{x−1x−1+x}=1(2)limx→0−{x−1∣x−1∣−x}=limx→0+{x−1x−1−x}=1
Answered by bramlex last updated on 22/Jul/20

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