Question Number 104218 by bemath last updated on 20/Jul/20
$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left[\frac{\mathrm{ln}\:\left(\mathrm{1}+{x}\right)+\underset{{n}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\left[\frac{\left(\mathrm{1}+{x}^{\mathrm{2}^{{n}} } \right)}{\left(\mathrm{1}−{x}^{\mathrm{2}^{{n}} } \right)}\right]^{\mathrm{2}^{−{n}} } }{\mathrm{ln}\:\left(\frac{\mathrm{1}}{\mathrm{1}−{x}}\right)}\right] \\ $$$$ \\ $$
Commented by Dwaipayan Shikari last updated on 20/Jul/20
$$\mathrm{1} \\ $$
Answered by bramlex last updated on 20/Jul/20