lim-x-1-lnx-0-x-dt-lnt- Tinku Tara June 4, 2023 Differential Equation 0 Comments FacebookTweetPin Question Number 91228 by ~blr237~ last updated on 28/Apr/20 limx→1lnx(∫0xdtlnt) Commented by abdomathmax last updated on 29/Apr/20 =limx→1(x−1)lnx×∫0x1lntdtx−1wehavelimx→1(x−1)lnx=0limx→1∫0x1lntdtx−1=limx→11lnx1(hospital)=limx→11lnx=∞.perhapsthislimitdontexist.. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: prove-that-a-b-sin-x-b-a-sin-x-2-dx-cos-x-b-a-sin-x-Next Next post: Question-25700 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.