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lim-x-1-x-1-x-2-1-




Question Number 121074 by bramlexs22 last updated on 05/Nov/20
 lim_(x→1)  ((x−1)/( (√(x^2 −1))))?
limx1x1x21?
Answered by liberty last updated on 05/Nov/20
 lim_(x→1)  ((x−1)/( (√((x−1)(x+1))))) = lim_(x→1)  (√((x−1)/(x+1))) = 0
limx1x1(x1)(x+1)=limx1x1x+1=0
Answered by liberty last updated on 05/Nov/20
L′Hopital    lim_(x→1)  ((x−1)/( (√(x^2 −1)))) = lim_(x→1)  (1/([(x/( (√(x^2 −1))))]))  = lim_(x→1)  ((√(x^2 −1))/x) = 0
LHopitallimx1x1x21=limx11[xx21]=limx1x21x=0

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