lim-x-1-x-2-x-1-x-1-

Question Number 121222 by benjo_mathlover last updated on 06/Nov/20

\lim_{x \to - \infty} \frac{\sqrt{1 + x^{2}} - x + 1}{x + 1} ?

Answered by liberty last updated on 06/Nov/20

\lim_{x \to - \infty} \frac{∣ x ∣ \sqrt{1 + \frac{1}{x^{2}}} - x (1 - \frac{1}{x})}{x (1 + \frac{1}{x})} =

\lim_{x \to - \infty} \frac{- x (\sqrt{1 + \frac{1}{x^{2}}} + (1 - \frac{1}{x}))}{x (1 + \frac{1}{x})} = - 2 .

Facebook Tweet Pin