lim-x-2-x-2-e-x-4e-2-x-2-

Question Number 154390 by liberty last updated on 18/Sep/21

\lim_{x \to 2} \frac{x^{2} e^{x} - 4 e^{2}}{x - 2} ?

Commented by puissant last updated on 18/Sep/21

= \lim_{x \to 2} (2 {x e}^{x} + x^{2} e^{x}) = 4 e^{2} + 4 e^{2} = 8 e^{2} . .

Answered by yeti123 last updated on 18/Sep/21

\lim_{x \to 2} \frac{x^{2} e^{x} - 4 e^{2}}{x - 2} = \lim_{x \to 2} \frac{2 {x e}^{x} + x^{2} e^{x}}{1}

= \lim_{x \to 2} e^{x} (2 x + x^{2})

= 8 e^{2}

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