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lim-x-4-x-3-x-x-x-2-x-1-

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Question Number 92423 by mhmd last updated on 06/May/20
lim_(x⇒∞) ((4(x+3)!−x!)/(x[(x+2)!−(x−1)!]))
limx⇒∞4(x+3)!−x!x[(x+2)!−(x−1)!]
Answered by john santu last updated on 07/May/20
lim_(x→∞) ((4(x+3)(x+2)(x+1)x!−x!)/(x(x+2)(x+1)x!−x(x−1)!)) lim_(x→∞) ((x! (4(x+3)(x+2)(x+1)−1))/(x! (x(x+2)(x+1)−1))) lim_(x→∞) ((4(x+3)(x+2)(x+1)−1)/(x(x+2)(x+1)−1)) = 4
limx→∞4(x+3)(x+2)(x+1)x!−x!x(x+2)(x+1)x!−x(x−1)!limx→∞x!(4(x+3)(x+2)(x+1)−1)x!(x(x+2)(x+1)−1)limx→∞4(x+3)(x+2)(x+1)−1x(x+2)(x+1)−1=4

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