Question Number 191874 by Subhi last updated on 02/May/23
$${lim}_{{x}\Rightarrow\infty} \frac{{e}^{{x}+\mathrm{1}} +{pi}^{{x}−\mathrm{1}} }{{e}^{{x}−\mathrm{1}} +{pi}^{{x}+\mathrm{1}} } \\ $$$$ \\ $$
Answered by mehdee42 last updated on 03/May/23
$${lim}_{{x}\rightarrow\infty} \:\frac{{e}\left(\frac{{e}}{\pi}\right)^{{x}} +\pi^{−\mathrm{1}} }{{e}^{−\mathrm{1}} \left(\frac{{e}}{\pi}\right)^{{x}} +\pi}\:=\frac{\mathrm{1}}{\pi^{\mathrm{2}} } \\ $$