Question Number 30657 by NECx last updated on 23/Feb/18
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{e}^{−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}} \\ $$
Commented by Cheyboy last updated on 23/Feb/18
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}{e}^{−\:\frac{\infty^{\mathrm{2}} }{\mathrm{2}}} \\ $$$$ \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{e}^{−\infty} \\ $$$$ \\ $$$$\underset{{x}\rightarrow\infty\:} {\mathrm{lim}}\:\frac{\mathrm{1}}{{e}^{\infty} } \\ $$$$\:{As}\:{x}\:{increases}\:{approching}\:\Rightarrow\infty\: \\ $$$$\frac{\mathrm{1}}{{e}^{\infty} }\:{approches}\:\mathrm{0} \\ $$$$ \\ $$$${Hence}\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{1}}{{e}^{\infty} }\:=\mathrm{0} \\ $$$$ \\ $$
Commented by NECx last updated on 25/Feb/18
$${thank}\:{you}\:{sir}. \\ $$