lim-x-pi-2-cos-x-sin-x-cos-x-1-3-sin-x- Tinku Tara June 4, 2023 Limits 0 Comments FacebookTweetPin Question Number 161319 by cortano last updated on 16/Dec/21 limx→π2cosxsinx+cosx3−sinx=? Answered by som(math1967) last updated on 16/Dec/21 limx→π2cosx{(sinx+cosx)23+(sinx+cosx)13sinx+sin2x}sinx+cosx−sin3xlimx→π2cosx{(sinx+cosx)23+(sinx+cosx)13sinx+sin2x}sinx(1−sin2x)+cosxlimx→π2cosx{(sinx+cosx)23+(sinx+cosx)13sinx+sin2x}cosx(sinxcosx+1)limx→π2{(sinx+cosx)23+(sinx+cosx)13sinx+sin2x}sinxcosx+11+1+10+1=3 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-95780Next Next post: it-looks-version-2-077-has-a-problem-for-very-long-loading- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.