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Lim-x-pi-2-sinx-sinx-sinx-1-sinx-logsinx-a-4-b-2-c-1-2-d-none-




Question Number 190182 by SLVR last updated on 29/Mar/23
Lim_(x→π/2) ((sinx−sinx^(sinx) )/(1−sinx+logsinx))  a)4        b)2          c)1/2        d)none
Limxπ/2sinxsinxsinx1sinx+logsinxa)4b)2c)1/2d)none
Commented by SLVR last updated on 29/Mar/23
kindly help me
kindlyhelpme
Commented by SLVR last updated on 29/Mar/23
i tried but by LHospital Rule  its too lenghty..
itriedbutbyLHospitalRuleitstoolenghty..
Commented by Frix last updated on 29/Mar/23
Let sin x =t; t→1  Now l′Ho^� pital is possible ⇒ lim=2
Letsinx=t;t1NowlHopital^ispossiblelim=2
Commented by SLVR last updated on 29/Mar/23
Great....sir.Thanks
Great.sir.Thanks

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