lim-x-pi-2-tan-2-x-x-pi-2-cos-2-x- Tinku Tara June 4, 2023 Limits 0 Comments FacebookTweetPin Question Number 105661 by bobhans last updated on 30/Jul/20 limx→π/2tan2x(x−π2)−cos2x? Commented by Dwaipayan Shikari last updated on 30/Jul/20 limitdoesn′texist Answered by bemath last updated on 30/Jul/20 setx=π2+mlimm→0m−sin2(π2+m)cot2(π2+m)limm→0m−cos2(m)tan2m=mlimm→01−cos2mmtan2m=mlimx→01−cos2m2mtan2m=mlimm→01−(1−m22)2 Answered by Dwaipayan Shikari last updated on 30/Jul/20 limx→π−2tan2xx−π2−h−cos2x→i∞{(h→0)(L.H.S)(R.H.S)limx→π+2tan2xx−π2+h−cos2x→∞R.H.S≠L.H.S Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: study-the-convergence-of-v-n-k-1-n-1-k-1-2-k-ln-k-Next Next post: evaluate-0-pi-log-a-cos-x-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.