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lim-x-pi-8-cot-4x-cos-4x-pi-8x-3-




Question Number 115195 by bemath last updated on 24/Sep/20
lim_(x→(π/8))  ((cot 4x−cos 4x)/((π−8x)^3 )) ?
limxπ8cot4xcos4x(π8x)3?
Answered by bobhans last updated on 24/Sep/20
let x = (π/8)+p ; p→0  lim_(p→0)  ((cot (4p+(π/2))−cos (4p+(π/2)))/((−8p)^3 )) =  lim_(p→0)  ((−tan 4p+sin 4p)/(−512p^3 )) =   lim_(p→0)  ((tan 4p−sin 4p)/(512p^3 )) = lim_(p→0)  ((tan 4p(1−cos 4p))/(512p^3 ))  = ((4×8)/(64×8)) = (1/(16))
letx=π8+p;p0limp0cot(4p+π2)cos(4p+π2)(8p)3=limp0tan4p+sin4p512p3=limp0tan4psin4p512p3=limp0tan4p(1cos4p)512p3=4×864×8=116

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