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Question Number 84364 by jagoll last updated on 12/Mar/20
lim_(x→π)  (((√π)−(√(π+4x)))/(cos (((π(x+1))/2)))) = ?
limxπππ+4xcos(π(x+1)2)=?
Answered by john santu last updated on 12/Mar/20
(√π) × lim_(x→π)  ((1−(√(1+((4x)/π))))/(−sin (((πx)/2)))) =  −(√π) × lim_(x→π)  ((1−(1+((2x)/π)+o(x)))/((πx)/2))=  −(√π) ×(2/π)×−(2/π) = ((4(√π))/π^2 )
π×limxπ11+4xπsin(πx2)=π×limxπ1(1+2xπ+o(x))πx2=π×2π×2π=4ππ2

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