lim-x-x-2-1-x-2-1-1-5-with-solution-

Question Number 186617 by mustafazaheen last updated on 07/Feb/23

\underset{x \to \infty}{l i m} \frac{x^{2} - 1}{\sqrt[5]{(x^{2} - 1)}} = ? w i t h s o l u t i o n

Commented by aba last updated on 07/Feb/23

= \lim_{x \to \infty} \sqrt[5]{\frac{{(x^{2} - 1)}^{5}}{(x^{2} - 1)}} = \lim_{x \to \infty} \sqrt[5]{{(x^{2} - 1)}^{4}} = \infty

Commented by aba last updated on 07/Feb/23

= \lim_{x \to \infty} \frac{1 - \frac{1}{x^{2}}}{\sqrt[5]{\frac{1}{x^{8}} - \frac{1}{x^{10}}}} = \frac{1}{0} = \infty

Answered by cortano1 last updated on 07/Feb/23

\lim_{x \to \infty} \sqrt[5]{{(x^{2} - 1)}^{4}} = \infty

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