Question Number 23190 by ANTARES_VY last updated on 27/Oct/17
$$\underset{\boldsymbol{\mathrm{x}}\rightarrow\infty} {\boldsymbol{\mathrm{lim}}}\left(\frac{\boldsymbol{\mathrm{x}}−\mathrm{2}}{\mathrm{3}\boldsymbol{\mathrm{x}}+\mathrm{10}}\right)^{\mathrm{5}\boldsymbol{\mathrm{x}}} \\ $$
Commented by ANTARES_VY last updated on 27/Oct/17
$$\boldsymbol{\mathrm{calculate}} \\ $$
Answered by ajfour last updated on 27/Oct/17
$$=\left(\frac{\mathrm{1}}{\mathrm{3}}\right)^{\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\mathrm{5}{x}\right)\:} =\mathrm{0} \\ $$