lim-x-x-x-2-1-x-

Question Number 90432 by jagoll last updated on 23/Apr/20

\lim_{x \to - \infty} x [\sqrt{x^{2} + 1} - x] = ?

Commented by mathmax by abdo last updated on 23/Apr/20

w e h a v e {l i m}_{x \to - \infty} x = - \infty a n d

{l i m}_{x \to - \infty} \sqrt{x^{2} + 1} - x = + \infty \Rightarrow {l i m}_{x \to - \infty} x (\sqrt{x^{2} + 1} - x) = - \infty

Answered by jagoll last updated on 23/Apr/20

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