Question Number 100037 by bobhans last updated on 24/Jun/20
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{x}\sqrt{\mathrm{x}}\:\mathrm{sin}\:\left(\mathrm{2x}\right)\:? \\ $$
Commented by bramlex last updated on 24/Jun/20
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{x}\sqrt{{x}}\:=\:\infty\:\wedge\:−\mathrm{1}\leqslant\:\mathrm{sin}\:\mathrm{2}{x}\:\leqslant\:\mathrm{1} \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}{x}\sqrt{{x}}\:\mathrm{sin}\:\mathrm{2}{x}\:=\:\infty\: \\ $$
Commented by Dwaipayan Shikari last updated on 24/Jun/20
$$\infty \\ $$