Question Number 80748 by jagoll last updated on 06/Feb/20

Commented by john santu last updated on 06/Feb/20

Commented by jagoll last updated on 06/Feb/20

Commented by mathmax by abdo last updated on 06/Feb/20

Answered by MJS last updated on 06/Feb/20
![lim_(x→∞) (((x!)/x^x ))^(1/x) = [x!≈(x^x /e^x )(√(2πx)) Sterling′s approximation] =(1/e)lim_(x→∞) (2πx)^(1/(2x)) =(1/e) [lim_(x→∞) C_1 ^(1/x) =1 ∀C_1 >0] [lim_(x→∞) x^(1/(C_2 x)) =lim_(x→∞) e^((ln x)/(C_2 x)) =10^0 =1 ∀C_2 ≠0]](https://www.tinkutara.com/question/Q80759.png)
Commented by jagoll last updated on 06/Feb/20

Commented by MJS last updated on 06/Feb/20

Commented by jagoll last updated on 06/Feb/20
