log-2-x-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 27282 by hp killer last updated on 04/Jan/18 ∫log(2+x2)dx Commented by abdo imad last updated on 04/Jan/18 ifyoumeanlnintegrateparpartsu′=1andv=ln(2+x2)∫ln(2+x2)dx=xln(2+x2)−∫x2x2+x2dx=xln(2+x2)−2∫x22+x2dx=xln(2+x2)−2∫2+x2−22+x2dx=xln(2+x2)−2x+4∫dx2+x2andbythechangementx=2t∫dx2+x2=∫2dt2+2t2=22artan(x2)so∫ln(2+x2)dx=xln(2+x2)−2x+22arctan(x2). Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-pi-4-x-sin-pi-4-x-2cos-2x-1-4-Next Next post: Question-158358 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.