log-2-x-log-3-x-1-x-

Question Number 86515 by jagoll last updated on 29/Mar/20

\log_{2} (x) + \log_{3} (x) = 1

x =

Commented by john santu last updated on 29/Mar/20

\Rightarrow^{2} \log x =^{2} \log 3 .^{3} \log x

\Leftrightarrow^{3} \log (x) {^{2} \log 3 + 1} = 1

^{3} \log x = \frac{1}{^{2} \log 6} =^{6} \log 2

x = 3^{^{6} \log 2}

Commented by jagoll last updated on 29/Mar/20

thank you

Facebook Tweet Pin