log-2-x-log-4-y-4-x-y-8- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 88663 by mary_ last updated on 12/Apr/20 {log2x+log4y=4x.y=8 Answered by jagoll last updated on 28/Apr/20 log2(x)+12log2(8x)=4log2(x)+log28x=log2(16)x8x=16⇒8x=256x=2568=32soy=832=4−1 Commented by john santu last updated on 12/Apr/20 correctionsiritshouldbelog2(x)+log28x=4⇒x8x=16⇒8x=16x=16.168=32.theny=832=14 Commented by jagoll last updated on 12/Apr/20 ooyes.thankyoumrjohn Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: x-sinx-1-cosx-dx-please-help-me-Next Next post: 0-ln-1-x-x-x-2-x-1-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.