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log-2-x-log-4-y-4-x-y-8-




Question Number 88663 by mary_ last updated on 12/Apr/20
 { ((log_2 x+log_4 y=4)),((x.y=8)) :}
{log2x+log4y=4x.y=8
Answered by jagoll last updated on 28/Apr/20
log_2 (x)+(1/2)log_2 ((8/x)) =4  log_2 (x) +log_2  (√(8/x)) = log_2  (16)  x(√(8/x)) = 16 ⇒(√(8x)) = (√(256))  x = ((256)/8) = 32 so y = (8/(32)) = 4^(−1)
log2(x)+12log2(8x)=4log2(x)+log28x=log2(16)x8x=168x=256x=2568=32soy=832=41
Commented by john santu last updated on 12/Apr/20
correction sir  it should be   log_2 (x)+log_2  (√(8/x)) = 4  ⇒ x(√(8/x)) = 16 ⇒ (√(8x)) = 16  x = ((16.16)/8) = 32 . then y = (8/(32)) = (1/4)
correctionsiritshouldbelog2(x)+log28x=4x8x=168x=16x=16.168=32.theny=832=14
Commented by jagoll last updated on 12/Apr/20
oo yes. thank you mr john
ooyes.thankyoumrjohn

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