Question Number 175104 by blackmamba last updated on 19/Aug/22
$$\:\:\mathrm{log}\:_{\mathrm{3}} \left({a}+\mathrm{1}\right)=\mathrm{log}\:_{\mathrm{4}} \left({a}+\mathrm{8}\right) \\ $$$$\:{a}=? \\ $$
Answered by MJS_new last updated on 19/Aug/22
$${a}+\mathrm{8}=\mathrm{4}^{{x}} \wedge{a}+\mathrm{1}=\mathrm{3}^{{x}} \:\Rightarrow\:{x}=\mathrm{2}\wedge{a}=\mathrm{8} \\ $$