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log-4-5x-6-log-x-256-8-




Question Number 106024 by john santu last updated on 02/Aug/20
log _4 (5x−6).log _x (256)=8
log4(5x6).logx(256)=8
Commented by Dwaipayan Shikari last updated on 02/Aug/20
{2,3}
{2,3}
Answered by Dwaipayan Shikari last updated on 02/Aug/20
((log(5x−6).log(256))/(log(4).log(x)))=8  ((log(5x−6).8log(2))/(2log(2)log(x)))=8  ((log(5x−6))/(log(x)))=2  5x−6=e^(2log(x))   5x−6=x^2   x^2 −5x+6=0   { ((x=2)),((x=3)) :}
log(5x6).log(256)log(4).log(x)=8log(5x6).8log(2)2log(2)log(x)=8log(5x6)log(x)=25x6=e2log(x)5x6=x2x25x+6=0{x=2x=3
Answered by bemath last updated on 02/Aug/20
(1/2)×8 log _2 (5x−6).log _x (2)=8  log _2 (5x−6)=2.log _2 (x)  x^2 −5x+6=0  x = 2 & x = 3
12×8log2(5x6).logx(2)=8log2(5x6)=2.log2(x)x25x+6=0x=2&x=3

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