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log-5-x-2-log-8-x-4-log-6-x-1-




Question Number 93847 by i jagooll last updated on 15/May/20
log _5  (x−2)+log _8  (x−4)= log _6 (x−1)
log5(x2)+log8(x4)=log6(x1)
Commented by john santu last updated on 15/May/20
  ((ln(x−2))/(ln5))+((ln(x−4))/(ln8))=((ln(x−1))/(ln6))   x > 4 for x ∈R  ln(x−2)^(0.62) +ln(x−4)^(0.48) =ln(x−1)^(0.59)   ln(x−2)^(0.62) .(x−4)^(0.48) =ln(x−1)^(0.59)   (x−2)^(0.62) .(x−4)^(0.48)  = (x−1)^(0.59)
ln(x2)ln5+ln(x4)ln8=ln(x1)ln6x>4forxRln(x2)0.62+ln(x4)0.48=ln(x1)0.59ln(x2)0.62.(x4)0.48=ln(x1)0.59(x2)0.62.(x4)0.48=(x1)0.59
Commented by i jagooll last updated on 15/May/20
What the value of x sir?
Whatthevalueofxsir?

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