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log-9-x-7-2-log-3-4-x-2-log-3-4-x-7-2-




Question Number 92319 by jagoll last updated on 06/May/20
log _9 (x+(7/2)).log _(3/4) (x^2 ) ≥   log _(3/4) (x+(7/2))
log9(x+72).log3/4(x2)log3/4(x+72)
Commented by john santu last updated on 06/May/20
 { ((x+(7/2) > 0 ⇒ x > −(7/2))),((x^2  > 0 ⇒ x ≠ 0)) :}  (1/2)log _3 (x+(7/2)).((log _3 (x^2 ))/(log _3 ((3/4)))) ≥ ((log _3 (x+(7/2)))/(log _3 ((3/4))))  log _3 (x+(7/2)) ((1/2)log _3 (x^2 )−1) ≤ 0  (−(7/2),−3] ∪ [−(5/2),0 ) ∪ (0,3)
{x+72>0x>72x2>0x012log3(x+72).log3(x2)log3(34)log3(x+72)log3(34)log3(x+72)(12log3(x2)1)0(72,3][52,0)(0,3)
Commented by jagoll last updated on 06/May/20
Is this the cut step? why so short?
Commented by jagoll last updated on 06/May/20
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