Question Number 92980 by john santu last updated on 10/May/20
$$\mathrm{log}\:_{\sqrt[{\mathrm{3}\:\:}]{\mathrm{9}{x}}} \:\left(\sqrt{\frac{{x}^{\mathrm{3}} }{\mathrm{3}}}\right)\:+\:\mathrm{log}\:_{\sqrt[{\mathrm{3}\:\:}]{\mathrm{3}{x}^{\mathrm{2}} }} \left(\sqrt{\mathrm{27}{x}}\right)\:\leqslant\:\mathrm{3} \\ $$
Answered by frc2crc last updated on 10/May/20
$$\frac{\mathrm{1}}{\mathrm{9}}<{x}<\frac{\sqrt{\mathrm{3}}}{\mathrm{3}}\:{or}\:\mathrm{3}^{\mathrm{1}/\mathrm{3}} \leqslant{x}\leqslant\mathrm{3} \\ $$
Commented by john santu last updated on 10/May/20
$$\mathrm{good}\: \\ $$