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log-e-1-cox-1-cosx-differentiate-w-r-t-x-




Question Number 19860 by vivek last updated on 16/Aug/17
log_e (√(((1−cox)/(1+cosx))  differentiate w.r.t x))
loge1cox1+cosxdifferentiatew.r.tx
Answered by myintkhaing last updated on 17/Aug/17
(d/dx) (log_e  ((sin x)/(1+cos x)))  = (((1+cos x)/(sin x)))((((1+cos x)cos x−sin x(−sin x))/((1+cos x)^2 )))  = (1/(sin x)) = cosec x
ddx(logesinx1+cosx)=(1+cosxsinx)((1+cosx)cosxsinx(sinx)(1+cosx)2)=1sinx=cosecx
Commented by myintkhaing last updated on 16/Aug/17
we use in our country ...  sine → sin              cosecant→cosec  cosine→cos          secant→sec  tangent→tan     cotangent→cot
weuseinourcountrysinesincosecantcoseccosinecossecantsectangenttancotangentcot
Commented by Joel577 last updated on 17/Aug/17
(1/(sin x)) = cosec x
1sinx=cosecx
Commented by vivek last updated on 17/Aug/17
sir answer is cosec x
siransweriscosecx

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