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log-e-e-2-x-lnx-log-e-x-3-faind-x-

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Question Number 169798 by mathlove last updated on 09/May/22
log_e (e^2 x^(lnx) )=log_e (x^3 ) faind x=?
loge(e2xlnx)=loge(x3)faindx=?
Commented by cortano1 last updated on 09/May/22
⇒2+(ln x)^2 = 3 ln x ⇒(ln x)^2 −3 ln x+2 = 0 ⇒ { ((ln x=2⇒x=e^2 )),((ln x=1⇒x= e)) :}
⇒2+(lnx)2=3lnx⇒(lnx)2−3lnx+2=0⇒{lnx=2⇒x=e2lnx=1⇒x=e
Commented by mathlove last updated on 09/May/22
thanks
thanks

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