log-x-1-x-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 151501 by talminator2856791 last updated on 21/Aug/21 ∫(logx+1)xxdx Answered by puissant last updated on 21/Aug/21 K=∫(1+lnx)xxdxxx=exlnxddxexlnx=(1+lnx)xx⇒K=xx+C Commented by Olaf_Thorendsen last updated on 21/Aug/21 xx=exlnxddxxx=ddxexlnx=(1+lnx)exlnx=(1+lnx)xxK=xx+C Commented by Tawa11 last updated on 22/Aug/21 Sir,helpmecheckQ151636 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-x-1-2-x-1-ln-2-x-1-dx-Next Next post: 0-ln-x-x-x-1-2x-1-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.