log-x-2-2-x-2-4x-

Question Number 167746 by mathlove last updated on 24/Mar/22

{l o g}_{(x^{2} + 2)} (x^{2} + 4 x) = ?

Commented by MJS_new last updated on 24/Mar/22

\log_{x^{2} + 2} (x^{2} + 4 x) = \frac{\ln (x^{2} + 4 x)}{\ln (x^{2} + 2)} = \frac{\ln x + \ln (x + 4)}{\ln (x^{2} + 2)}

\Rightarrow

x > 0

Answered by LEKOUMA last updated on 24/Mar/22

\log_{(x^{2} + 2)} (x^{2} + 4 x) = \frac{\log (x^{2} + 4 x)}{\log (x^{2} + 2)}

Commented by MJS_new last updated on 24/Mar/22

you cannot find x because {there}^{'} s no equation

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