log-x-2-x-2-log-16x-x-3-40log-4x-x-0-

Question Number 84997 by M±th+et£s last updated on 18/Mar/20

{l o g}_{\frac{x}{2}} x^{2} - {l o g}_{16 x} x^{3} + 40 {l o g}_{4 x} \sqrt{x} = 0

Commented by jagoll last updated on 18/Mar/20

\frac{\log_{2} (x^{2})}{\log_{2} (x) - 1} - \frac{\log_{2} (x^{3})}{\log_{2} (x) + 4} + \frac{40 \log_{2} (\sqrt{x})}{\log_{2} (x) + 2} = 0

let \log_{2} (x) = t

\frac{2 t}{t - 1} - \frac{3 t}{t + 4} + \frac{20 t}{t + 2} = 0

t [\frac{2}{t - 1} - \frac{3}{t + 4} + \frac{20}{t + 2}] = 0

Commented by jagoll last updated on 18/Mar/20

now easy to solve

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