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log-x-3-3x-54-log-3-x-18-3log-x-3-x-2-x-




Question Number 161362 by cortano last updated on 17/Dec/21
 log _(√(x/3)) (3x−54)^(log _3 (x))  = 18−3log _(x/3) (x^2 )   x=?
logx3(3x54)log3(x)=183logx3(x2)x=?
Commented by bobhans last updated on 17/Dec/21
 ((log _3 (x)[1+log _3 (x−18)])/((1/2)[log _3 (x)−1])) = 18−((6 log _3 (x))/(log _3 (x)−1))   ((2 log _3 (x)[1+log _3 (x−18)])/(log _3 (x)−1)) = ((12 log _3 (x)−18)/(log _3 (x)−1))   2log _3 (x)+2log _3 (x)log _3 (x−18)=12log _3 (x)−18   log _3 (x)log _3 (x−18)−5log _3 (x)+9 = 0
log3(x)[1+log3(x18)]12[log3(x)1]=186log3(x)log3(x)12log3(x)[1+log3(x18)]log3(x)1=12log3(x)18log3(x)12log3(x)+2log3(x)log3(x18)=12log3(x)18log3(x)log3(x18)5log3(x)+9=0

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