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log-x-6-log-10-6-x-log-10-x-gt-log-10-x-x-




Question Number 85433 by jagoll last updated on 22/Mar/20
−log_(((x/6))) (((log_(10) (√(6−x)))/(log_(10) x))) > log_(10) (((∣x∣)/x))
log(x6)(log106xlog10x)>log10(xx)
Answered by jagoll last updated on 22/Mar/20

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