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log-x-x-3-7-lt-log-x-3-7-




Question Number 85694 by john santu last updated on 24/Mar/20
log_(((x/(x−3)))) (7) < log_(((x/3)))  (7)
log(xx3)(7)<log(x3)(7)
Commented by jagoll last updated on 24/Mar/20
(1/(log_7 ((x/(x−3))))) < (1/(log_7 ((x/3))))  (1) (x/(x−3)) > 0 ∧ (x/3)>0   ⇒ x > 3  (2) log_7 ((x/3)) < log_7 ((x/(x−3)))  (x/3)− (x/(x−3)) < 0  ((x(x−6))/(3(x−3))) < 0 ⇒ x<0 ∨3 < x < 6  the solution ⇒ 3 < x < 6
1log7(xx3)<1log7(x3)(1)xx3>0x3>0x>3(2)log7(x3)<log7(xx3)x3xx3<0x(x6)3(x3)<0x<03<x<6thesolution3<x<6

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