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logx-2-log-2-x-6-3-solve-for-x-




Question Number 54827 by problem solverd last updated on 12/Feb/19
logx^2 +log_2 (x−6)=3  solve for x
$$\mathrm{logx}^{\mathrm{2}} +\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}−\mathrm{6}\right)=\mathrm{3} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{x} \\ $$

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