loving-questions-of-the-form-if-then-find-the-sum-product-etc-of-so-please-solve-these-1-if-and-are-the-solutions-of-x-2-x-12-0-then-find-cosh-cot-2-if-a-b-2-and-a-b-0-then-find-

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Question Number 113393 by Her_Majesty last updated on 13/Sep/20

$$lovingquestionsoftheform$$$$“if\dots thenfindthesum/product/etc.of\dots$$$$sopleasesolvethese:$$$$\left(1\right)$$$$if\gamma and\lambda arethesolutionsof$$$$x^2+x-12=0thenfindcosh\lambda -cot\gamma$$$$\left(2\right)$$$$ifa+b=2anda-b=0thenfind$$$$\int x^{\frac{a+b}{2ab}}ln(-e^{i\pi a}-x)ln(e^{{cos}^{-1}b}-x)dx$$$$areyouintelligentenough?$$$$thenpleasepleasepleasesirormadam$$$$helpme!!!Ineedananswer\mathbf{urgentliest}!!!!$$$$goodluck!$$$$\left(c\right)by\mathbb{H}\mathfrak{e}\mathcal{R}\mathfrak{M}\mathit{a}\mathbb{J}ϵ\int t\mathcal{Y}20200913$$

Commented by john santu last updated on 13/Sep/20

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Commented by malwaan last updated on 13/Sep/20

$$x^2+x-12=0$$$$\Rightarrow (x-3)(x+4)=0$$$$\therefore solutionset=\{3;-4\}$$$$\left(i\right)\gamma =3;\lambda =-4\Rightarrow cosh(-4)-cot\left(3\right)=34.32349$$$$\left(ii\right)\gamma =-4;\lambda =3\Rightarrow cosh\left(3\right)-cot(-4)=10.93135$$

Commented by malwaan last updated on 13/Sep/20

$$\left(2\right)a+b=2;a-b=0$$$$\Rightarrow a=1;b=1$$$$\therefore \int xln(1-x)ln(1-x)dx=$$$$\int x{\left[ln(1-x)\right]}^{2}dx=\dots$$

Commented by Rasheed.Sindhi last updated on 13/Sep/20

$$PerhapsHerMajestywantedto$$$$giveamessage!$$

Commented by malwan last updated on 13/Sep/20

$$whatisthepointplease?$$$$Iamsureyou{don}^{,}tneedhelp$$$$butwe\left[atleastme\right]do$$$$$$

Commented by Her_Majesty last updated on 13/Sep/20

$$onepointis,$$$$\left(youpostaquestion\right)\Rightarrow \left(youneedhelp\right)$$$$noneedtopostthesamequestionoverand$$$$overagain.l$$$$anotherpointis,peoplewhopostquestions$$$$toshowusweareunabletosolvethemwhile$$$$theythemselvesareableto,ruintheforum.$$$$a{3}^{rd}pointis,{it}^{\prime }suselesstosolvei.e.a$$$$polynomeandaskfori.e.“7x_1-13x_2+1/x_3^{″}$$$$because{there}^{\prime }snotakeawayfromthis.$$$$indeedthereisifyouaskfor“1/x_1+1/x_2+$$$$+1/x_3^{″}\dots \Rightarrow \mathrm{\exists }\left(sillyquestions\right)$$$$4^{th}.ifyoupostsomethingtodayeverybody$$$$canseeitwasYOUandTODAY.noneedto$$$$statethesefactsagain.$$

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