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M-0-x-2n-lnx-x-2-1-dx-

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Question Number 148942 by ArielVyny last updated on 01/Aug/21
M=∫_0 ^(+∞) ((x^(2n) lnx)/(x^2 +1))dx
$${M}=\int_{\mathrm{0}} ^{+\infty} \frac{{x}^{\mathrm{2}{n}} {lnx}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$$$ \\ $$

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